MySql Select last row with 30 minutes difference in date

Answer 06/23/2020 Developer FAQ 6

<h3>Question</h3>

This is a followup to this question MySql Select rows with 30 minutes difference in date, albeit similar in concept the solution needed might be different.

I have a MySql-8.0/MariaDb-10.4 table that contains a list of site visits of different visitors:

I want to create a query that returns the last visit of each visit session, where the session definition is where the CreatedAt date is 30 min or more from the previous visits.

So in my case, I should be returning row 7 (Id column), row 12 and row 13. Note also that a session can be more than 30 minutes, as long as each visit succeeds a previous visit with less than 30min.

The neat solution suggest by @EugenRieck was as follows:

SELECT
  late.*
FROM activities AS late
LEFT JOIN activities AS early
  ON late.VisitorId=early.VisitorId
  AND late.CreatedAt>early.CreatedAt
  AND late.CreatedAt<=DATE_ADD(early.CreatedAt, INTERVAL +30 MINUTE)
WHERE early.Id IS NULL
-- Maybe: AND late.VisitorId='26924c19-3cd1-411e-a771-5ebd6806fb27'
-- Maybe: ORDER BY late.CreatedAt

It works great, but it works by returning the first visit in each visit session, not the last visit. I tried to modify to work as i wanted but with no luck. Please help.

<h3>Answer1:</h3>

This is a variant of gap-and-islands problem. But you can handle it using lead(). Just check if the next createdAt is over 30 minutes from the value in a given row. That is the last row for a session:

select a.*
from (select a.*,
             lead(createdAt) over (partition by visitorid order by createdat) as next_ca
      from activities a
     ) a
where next_ca > createdAt + interval 30 minute;

Usually, in this situation you would want the last row as well. You would get that with or next_ca is null.

来源：https://stackoverflow.com/questions/61443546/mysql-select-last-row-with-30-minutes-difference-in-date